1. It's kinda dumb. Can't write long code. Can't write multiple features. It can make you simple programs or functions but that's about where it ends

  2. Search "thumbs up emoji optimus" in youtube click the first video (of a channel named optimus)

  3. If you look at all the places in the world where porn is restricted or outright criminalized, it’s not exactly translating to being safer for women.

  4. But also porn leads to an abnormal behaviours could be admitted by men or women, in another word pedos and a lot more, porn sites are places in where those awful habits could grow in a weak soul, what you said could be controlled by a bunch of laws(heavenly laws if done the right way).

  5. First you will need to understand how much energy it will take to do what you are asking. A common energy unit is a Joule (J). It takes 4.184J of energy to change the temperature of 1 gram of water by 1 degree Kelvin (K). In reading some of the above comments, people have explained that your liquid water will freeze into ice before it reaches -50 C, but it looks like you are doing this for fun, and don’t really care about that aspect and so we can ignore the fact that there will be a phase change from liquid to solid even though that is what will happen and will change the energy requirement. So, in order to calculate the energy requirement, you’ll first need to convert the 1 liter of water to mass by using the density of water. The density of water is 1,000 g/L. So that means your 1L of water weighs 1,000 g. Now take that mass and multiply it by the specific heat of 4.184 J/g*K, which gives you 4184 J/K and what that means is it takes 4184J of energy to lower the temperature of 1L of water by 1 degree K. Kelvin is essentially the same as Celsius if you’re just looking at temperature change. So if your water is starting at 20C, and dropping to -50C (again not possible since your water will freeze and there are different energy requirements for a phase change, but just for fun), that means you have a change of 70C, so multiply 70C by 4184 J/K and that gives you a total amount of energy required of 292880 J. Now you will need to find a heat exchanger and a refrigerant that can lower the temp of your water. The amount of time it takes to lower the temp greatly depends on what heat exchanger you use and how much surface area it has for heat transfer. Since you are talking about 1L of water, you don’t need something very large. However it gets a bit complicated. First I think you will need to determine how quickly you want the cooling to take place rather than the other way around. Do you want it to occur in one minute or one hour or one day? Then based on that, the heat exchanger can be sized appropriately. Or if you already have a heat exchanger in mind, then you can use the characteristics of that heat exchanger to calculate the amount of time required. For example if you want the heat transfer to occur over one minute, then take the total energy required that we calculated earlier and divide it by 60 seconds. 292880J/60s = 4882, so we have an energy rate required of 4882 J/s in order to be able to cool 1L of water from 20C to -50C in one minute. So next you will need to find a heat exchanger and cooling medium that can provide you with that energy rate. Let’s start with the cooling medium that is used to lower the temp of your water. You need a refrigerant that can cool down to -50C. Ammonia is a common refrigerant and it can cool down to -50C. Next you’ll need to find a heat exchanger that can deliver the energy rate.

  6. Bro… , I don't even know how to thank you , you're a legend, thank you so so so so so so so so so so so so so so so much!!!!!!!!!!!!

  7. Glad to help. Are you considering studying chemical engineering in university, or just having fun with a side project? It’s funny how something that seems like a simple question actually has many many different factors for consideration.

  8. Well unfortunately, my country isn't that good place to study this branch, it more like putting your certificates on the wall like trophies and seeing them every morning on your way out to go to work as a cashier or a security guard, etc…, for the rest of your life , again thank you so much. It is just a side project.

  9. You can develop these relationships from the basic equations of thermodynamics and heat transfer.

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